Shell Programming and Scripting

I am writing a code to append some numbers in the beginning of each line in all the files present in a directory. The number of files are really huge. The files are numbered as 1.sco, 2.sco, 4.sco (Note: 3.sco is missing).
The files currently look like this:

1.sco

Code:

2 3
5 6
6 7

My task is to open each 1.sco, 2.sco and so on and add a number based on its file name at the beginning of each line in all files. This is what I intend, sample output:

1.sco

Code:

1 2 3
1 5 6
1 6 7

2.sco

Code:

2 2 3
2 1 5
2 6 7
2 3 5
2 7 8

I have written a code but not getting where actually the problem is?

Code:

for num in `seq 1 300000`; do
 test ! -f $num.sco && continue
 echo '%s/^/$num /g\nwq!' | ex - $num.sco
done

The first line is a loop which generates the numbers. Then second lines tests for the presence of file and third line adds a text in the beginning of each line. I am using Linux with BASH.

Is it the filename (without its extension) that you want to put in front of each line? If so, then try this:

Code:

for file in *.sco; do sed -i "s/^/$(basename $file .sco) /g" $file; done

Hi,

I think you are trying to do something like this,

Code:

#! /bin/bash
cd "/home/path"
for i in *.sco
do
  s=${i%.sco}
  if [ -f $i ];then
    sed "s/^/$s /" $i >tmp
    mv tmp $i
  fi
done

Cheers,
Ranga

Code:

for i in *.sco; do  awk -v A=`basename $i .sco`  '{print A,$0}' $i; done

You need to save the informaion in the same file then you can use System Variable FILENAME in awk.

Code:

for i in *.sco; do awk -v A=`basename $i .sco` '{a[NR]=$0;}END{for(i=1;i<=NR;i++){print A,a[i] >FILENAME;}}' $i; done

Cheers,
Ranga