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Array in Bash!

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# 1  
Old 03-09-2012
Array in Bash!
sorry I am new to the bash scripting since I was used to c shell programming. I am writting a script in bash for which I have to create an array in bash. I was able to do parse one variable through command line by doing": Lets say the below code is part of temp.bash and is called like:
temp.bash -n x -m z
Code:
 
while [ $1 ]; do
  if [ $1 == "-n" ]; then
     shift
       n=$i
   else [ $1 == "-m" ]
      shift
       name=$1
       shift
      fi
  done
echo $n
echo $name
 
O/P
x
z

I want a code such that is I pass temp.bash -n x y z -m l k z, the ouput should be
x y z
l k z
That is in an array. Currently I can only pass one character. Can anybody help?
Thanks in advance
# 2  
Old 03-09-2012
A string with spaces in it is not the same thing as an array.

I don't think your if-statement if [ $1 ] does precisely what you think it does.

I'd take a slightly different approach:

Code:
WHERE=""
# $# is the number of arguments.
# While the number of arguments is greater than 0, keep looping.
while [ "$#" -gt 0 ]
do
        case "$1" in
        -n)    WHERE="n"             ;;
        -m)    WHERE="name"          ;;

        *) # All other arguments

                case "$WHERE" in
                n)        n="$n $1"     ;;
                name)   name="$name $1" ;;
                *)        ;;
                esac

                ;;
        esac

        shift
done

# 3  
Old 03-09-2012
Thanks Corona688. I used the code but I am getting syntax error near unexpected token `"$WHERE"`
case "$WHERE" in
It might be verbose but I thought I will write it again what I used"
Code:
WHERE=""
 while ["$#" -gt 0 ]
 do
         case "$1" in
          -n)  WHERE="n"  ;;
          -m)  WHERE="name" ;;
              case "$WHERE" in
               n)   n="$n $1"
             name) name="$name $1"
              esac
           ;;
           esac
           shift
done
echo $n
echo $name

when I type temp.bash with this code like: temp.bash -n x y -m l k, I am expecting to get result:
x y
l k
instead I get the error message describe above.
# 4  
Old 03-09-2012
You forgot a line:

Code:
        *) # All other arguments

That's not pseudocode. The * accepts all arguments that weren't matched by -n or -m before it.

Also, you left some important spaces out of your while-statement:

Code:
while ["$#" -gt 0 ] # Wrong
while [ "$#" -gt 0 ] # Right

# 5  
Old 03-09-2012
Quote:
Originally Posted by dixits
while ["$#" -gt 0 ]
A space is required (non-optional) between [ and "
Code:
while [ "$#" -gt 0 ]

-----------------------------------------------------------
Corona688 has already answered.
Last edited by balajesuri; 03-09-2012 at 01:00 PM.. Reason: Late post
# 6  
Old 03-09-2012
Thanks Corona668. The while loop of not using space was a typo but the problem was using not using :
Code:
*) # All other arguments

Thanks once again.
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