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Shell Programming and Scripting

comparison of number in linux..

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# 1  
Old 03-05-2012
comparison of number in linux..
hi all experts,


Code:
i=1;
while [ $i -lt 5  ]
                do
echo $i
$i=$i+1

done

can I use

Code:
min=2
max=5

if  (($min > $ max))

then 
else
fi


are both correct?

I am always getting errors and need help of experts.

I want to print all integer values less than five.

Actally I want to know if I used WHILE correctly and secondly about the
condition.

if possible please also give idea about real value comparison.
# 2  
Old 03-05-2012
Code:
i=1;
while [ $i -lt 5  ]
do
    echo $i
    i=$(($i+1))
done

Code:
min=2
max=5

if  (($min > $max))
then
    echo "min > max"    
else
    echo "min <= max"
fi

# 3  
Old 03-05-2012
Always getting what errors? Be specific. Also say what your shell is please.

$i=$i+1 is not how you do math in shell.

If you have BASH:

Code:
((i++))

If you don't:

i=`expr $i + 1` Note the spaces, not optional.
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