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if condition error: test: 0403-004 Specify a parameter with this command

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# 1  
Old 03-04-2012
if condition error: test: 0403-004 Specify a parameter with this command
Hi all,

I would like to ask if there's something wrong with my if - else condition, i couldn't run the script perfectly due to the error in my if - else condition stating that "test: 0403-004 Specify a parameter with this command."

below is the snippet of my script

Code:
if [ [ "${logFileName}"=="${logfName}" ] && [ "${paramTblName}"=="${tblName}" ] && [ "${startTimeStamp}"=="${startTime}" ] ]
then echo "true"
else echo "false
fi

any comments/suggestions is very much appreciated

regards,
Ivan
# 2  
Old 03-04-2012
Try:
Code:
if [ "${logFileName}"=="${logfName}" ] && [ "${paramTblName}"=="${tblName}" ] && [ "${startTimeStamp}"=="${startTime}" ]

This User Gave Thanks to bartus11 For This Post:
jihmantiquilla
# 3  
Old 03-04-2012
Hi bartus11,

the code you had posted returned an error indicating that "syntax error on line 1 stdin".

Please advise

Regards,
Ivan
# 4  
Old 03-04-2012
Try single = instead of ==
This User Gave Thanks to Scrutinizer For This Post:
jihmantiquilla
# 5  
Old 03-05-2012
You need to make sure all arguments in "if" is white space delimited.
Code:
if [ "${logFileName}" = "${logfName}" -a "${paramTblName}" = "${tblName}" -a "${startTimeStamp}" = "${startTime}" ]
then 
  echo "true"
else 
  echo "false"
fi

# 6  
Old 03-05-2012
thanks for the quick response, i had managed to run the if -else condition statement.

thanks and regards,
ivan
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