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Return value error

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# 1  
Old 03-01-2012
Return value error
Hi All,

I am new to shell sciprting and i have written a small script to get the filename if it exists. I need to capture the file name using the script and i also need the exit status. The problem i am facing is,though my file does not exists, iam getting the exit status as '0'. Please help me out.

My scripts is as follows;

Code:
#!/usr/bin/ksh
folder='/stagep03/cca/data/'
cd $folder
wild='*'
dated=`date +%m%d%y`
filename=`ls -l $1$dated$wild | tail -1 |grep ^-|awk '{print $9}'`
echo $filename
echo $?

The output iam getting is;
Code:
$ sh test.ksh PROCESS1.CAIRP.SSZCKST.A_R.
ls: 0653-341 The file PROCESS1.CAIRP.SSZCKST.A_R.030112* does not exist.
0

Thanks in advance.
Last edited by Scott; 03-01-2012 at 07:48 AM.. Reason: Use code tags, please
# 2  
Old 03-01-2012
Remove the line "echo $filename". If do not want to remove, instead of "echo $0", check for $filename is not null.

Guru.
# 3  
Old 03-01-2012
Thanks for the reply,

I removed $filename and run the script..but still iam facing the same problem. If the output is as "ls: 0653-341 The file PROCESS1.CAIRP.SSZCKST.A_R.030112* does not exist." why the exit status is 0?
# 4  
Old 03-01-2012
exit status 0 means the previous command return is true, which means this was executed correctly.
$? gives the return of the previously executed command.

you are executing
Code:
echo $filename echo $?

This mean echo command ran successfully which is the last command before "echo $?"

your error is coming while executing "ls -l" but with echo.
# 5  
Old 03-01-2012
I have removed echo $filename from my scrip. Now my "echo $?" is next to "filename=`ls -l $1$dated$wild | tail -1 |grep ^-|awk '{print $9}'`"

the exit status should not be '0' if the file does not exist. right?.

but it is '0'.
# 6  
Old 03-01-2012
Quote:
Originally Posted by srinivasayedla
I have removed echo $filename from my scrip. Now my "echo $?" is next to "filename=`ls -l $1$dated$wild | tail -1 |grep ^-|awk '{print $9}'`"

the exit status should not be '0' if the file does not exist. right?.

but it is '0'.
You are having couple of sub shells which causing it to be $?=0.

Try this and check
Code:
#!/usr/bin/ksh
folder='/stagep03/cca/data/'
cd $folder
wild='*'
dated=`date +%m%d%y`
ls -l $1$dated$wild
echo $?

Please note, you are invoking the script with old bourne shell. This simply ignores the shebang of the script (ksh)

To cope with the pipes (subshell), ksh93 having pipefail option.
Code:
$ ls nofile | more
ls: nofile: No such file or directory
$ echo $?
0
$ set -o pipefail
$ ls nofile | more
ls: nofile: No such file or directory
$ echo $?
2 
$

# 7  
Old 03-01-2012
One possible rearrangement of your script to let Shell use filename globbing.
Note that the "ls -1" below is "ls hyphen-one" not "ls hyphen-ell".

Code:
#!/usr/bin/ksh
folder='/stagep03/cca/data/'
cd "${folder}"
dated="`date +%m%d%y`"
prefix="${1}${dated}"

test -f "${prefix}"* ; REPLY=$?
echo "REPLY=${REPLY}"

if [ ${REPLY} -eq 0 ]
then
        ls -1d "${prefix}"*
fi

Last edited by methyl; 03-01-2012 at 10:58 AM..
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