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Passing awk variables to shell

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# 8  
Old 02-29-2012
Please try to post the actual sample to save time.
You must remove the spaces in LHS to make available in UNIX.
Code:
eval $(awk -F: '/(Primary Group|Secondary Group|Home Directory|Login Shell)/ {gsub(/[ ][ ]*/,"",$1);print $1"=\""$2"\""}' file)

Code:
$ echo $PrimaryGroup
(451) testunix
$ echo $SecondaryGroup
dialer wheel webgroup
$ echo $HomeDirectory
/home/me
$ echo $LoginShell
/usr/bin/ksh
$

# 9  
Old 02-29-2012
It is not working for me
Code:
testhost$ eval $(awk -F: '/(Primary Group|Secondary Group|Home Directory|Login Shell)/ {gsub(/[ ][ ]*/,"",$1);print $1"=\""$2"\""}' output)
awk: syntax error near line 1
awk: illegal statement near line 1
testhost$ uname -a
SunOS testhost 5.8 Generic_117350-46 sun4u sparc SUNW,Sun-Fire-V240

# 10  
Old 02-29-2012
use nawk
This User Gave Thanks to clx For This Post:
urello
# 11  
Old 03-01-2012
Many thanks
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