Shell Programming and Scripting

Greetings experts. Searched the forums (perhaps not hard enough?) - Am searching for a method to capture all output from a log file following the nth occurrence of a known string.

Background:
Using bash, I want to monitor my Oracle DB alert log file. The script will count the total # of occurrences the string "ORA-" appears in alert_SID.log.

Code:

$ cat alert_SID.log | grep -v grep | grep "ORA-" | wc -l > curcnt.txt

Each time the script runs, it will get the current count of occurrences of the string "ORA-" and compare that count to that stored in the "curcnt.txt" text file. If the "newest" count is greater than the "current" count, then I would like to capture the alert log from the Nth occurrence (in this case, the value of "current") on and receive the contents of that file.

My thought process is that there should be a relatively straightforward way to parse my alert_SID.log up until the Nth occurrence and grab all output following.

Any constructive feedback and/or tips to get me pointed in the right direction is much appreciated.

Thanks,
CJ

Code:

awk '/ORA-/{i++}i>N' alert_SID.log

@bartus11

That appears to give me what I need. I appreciate the quick reply and minimal solution.

CJ