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Need help on " if condition" in shell

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Top Forums Shell Programming and Scripting Need help on " if condition" in shell
# 8  
Old 02-29-2012
I have a query regarding the same.....

Are the below two scripts/Examples do the same functionality

Code:
Examples 1
.....
.....
printf "SK_BTS04A_hiQ_01b\n" | grep "[a-zA-Z].*[a-zA-Z0-9_-]" >/dev/null 2>&1
if [[ $? -ne 0 ]]
then
    echo 1
.....
.....

Code:
Examples 2
.....
.....
elif [[ SK_BTS04A_hiQ_01b != [a-zA-Z]*([a-zA-Z0-9_-]) ]]
then
    echo 1
.....
.....

Last edited by methyl; 02-29-2012 at 06:47 AM.. Reason: please user code tags
# 9  
Old 02-29-2012
No, the regex equivalent of the second example would be:
Code:
grep '^[a-zA-Z][a-zA-Z0-9_-]*$'

This User Gave Thanks to Scrutinizer For This Post:
frintocf
# 10  
Old 02-29-2012
Data
Quote:
Originally Posted by Scrutinizer
No, the regex equivalent of the second example would be:
Code:
grep '^[a-zA-Z][a-zA-Z0-9_-]*$'


what would be equvalent to the first example....
# 11  
Old 02-29-2012
Code:
elif [[ SK_BTS04A_hiQ_01b != [a-zA-Z]*[a-zA-Z0-9_-] ]]

So that would mean that you are only interested in checking the first and the last character.
# 12  
Old 02-29-2012
Question
Quote:
Originally Posted by Scrutinizer
Code:
elif [[ SK_BTS04A_hiQ_01b != [a-zA-Z]*[a-zA-Z0-9_-] ]]

So that would mean that you are only interested in checking the first and the last character.

Hi,
should satisfy
"Name must start with letter [a-z][A-Z]." \
"The rest of the name must consist of a combination of" \
"letters, numbers, dashes, and/or underscores."

I am trying to achieve the same for both the examples. How can I go about it ?

Thanks
# 13  
Old 02-29-2012
Hi, see post #9 and your second example.
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