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using base name with awk

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# 1  
Old 02-22-2012
MySQL using base name with awk
Smilie

Code:
find . -type f -exec ls -l {} \; | awk '$5 $9 {print $5 $9}'

I would like $9 to be without path information, but simply the file name.
Thanks for any consideration.
Last edited by Franklin52; 02-22-2012 at 05:40 AM.. Reason: Please use code tags for code and data samples, thank you
# 2  
Old 02-22-2012
Code:
find . -type f -exec basename {} \;

This User Gave Thanks to balajesuri For This Post:
robin_simple
# 3  
Old 02-22-2012
Try:
Code:
awk -F'[ /]*' '$5 $NF {print $5 $NF}'

This User Gave Thanks to Scrutinizer For This Post:
robin_simple
# 4  
Old 02-22-2012
Please try this below command line , i am not currently in a unix box .

Code:
find . -type f -exec ls -1 {} \; | awk -F "/" '{ print $NF }'

This User Gave Thanks to codemaniac For This Post:
robin_simple
# 5  
Old 02-22-2012
Is there a way to have the name column along with the file byte size column have corresponding files and sizes in the same rows?

0 a
124 b
256 c
8 d
# 6  
Old 02-22-2012
Hi try this
Hi Robin,

Please try this,

Code:
find . -type f -exec ls -1 {} \; | sed 's/\(.*\)\///g' | xargs ls -l | awk '{print $4,$8;}'

with cheersSmilie,

shanmu
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