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# 1  
Old 02-21-2012
list files with a specific pattern
How can I list files with the following specific criteria?

Quote:
fsdfaf.log
fsaffa.log1
rwerw.log2
safsaf.log20120221
I am trying this $> ls *.log[12] or $>ls *.log? --> [globbing]

but it only gives me fsaffa.log1, rwerw.log2.
How can I get all three files with a simple selection criteria ?
Quote:
fsdfaf.log
fsaffa.log1
rwerw.log2
Last edited by kchinnam; 02-21-2012 at 05:18 PM.. Reason: color coded in blue
# 2  
Old 02-21-2012
Try:
Code:
ls *.log? *.log

# 3  
Old 02-21-2012
is there a way that I can do that in one go? may be using other methods!?
# 4  
Old 02-21-2012
This should help?

Code:
ls -l | egrep -e "*.log[1,2]$|*.log$"

--
David
# 5  
Old 02-21-2012
Quote:
Originally Posted by chirish
This should help?

ls -l | egrep -e "*.log[1,2]$|*.log$"

--
David
That egrep is broken.

egrep uses extended regular expressions (ERE), not sh pattern matching. "*." in an ERE is an undefined expression; the * needs to follow something so that it can act as a quantifier (in basic regular expressions, a leading asterisk is interpreted literally). Also, the "." matches any character, not just itself.

The regular expression equivalent of the sh pattern *.log is .*\.log$

Regards,
Alister
# 6  
Old 02-21-2012
Quote:
Originally Posted by kchinnam
is there a way that I can do that in one go? may be using other methods!?
Actually, Bartus11 suggestion is doing it in one go...
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