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Awk help required for formatting digits.

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# 1  
Old 02-21-2012
Awk help required for formatting digits.
Hi experts,

I have two values in the file :

For example :
partcamt = 72.90
partdamt=27.9

I need to convert these values into 6 digits and ignore the "." sign so that the desired desired output is :
total value= 0072000027900

Currently I am using the following code :
Code:
  partCamount=substr($0,175,6)
   partDamount=substr($0,187,5)
   partCamount1=sprintf("%06d",partCamount)
   partDamount1=sprintf("%06d",partDamount)

So I am getting the output as 0000720000270.

Can you please help.
# 2  
Old 02-21-2012
Perhaps printf can help?

i.e.
Code:
$ awk 'BEGIN { printf "%06d\n", 27.9*10^2 }' #err, x100, I suppose!
002790

Your approach seems very ad-hoc. Could you show some representative input data?
# 3  
Old 02-21-2012
Thanks Scott.

Here is the input file :

Code:
0116WORCE   STD       KAHN                YETTA     UF1929042101453                         112.00      58.40E

0115NORFO   STD       CHETKAUSKAS         LONGIE       M1922060502021                           0.00       0.00E

0115NORFO   STD       CHETKAUSKAS         FLORENCE     F1917122102021                           0.00       0.00E

0104MIDDL   STD       DRISCOLL            TERESA      CF1928122101867                         112.00      58.40E

Now I need to consider the last 2 records in the file(ignoring E) and merge them together (removing the decimal point) and total length would 12 characters each.
Each field would have total 6 characters after the decimal point is removed.
# 4  
Old 02-21-2012
I don't think awk will care about the "E":
Code:
$ cat file1
0116WORCE   STD       KAHN                YETTA     UF1929042101453                         112.00      58.40E
0115NORFO   STD       CHETKAUSKAS         LONGIE       M1922060502021                           0.00       0.00E
0115NORFO   STD       CHETKAUSKAS         FLORENCE     F1917122102021                           0.00       0.00E
0104MIDDL   STD       DRISCOLL            TERESA      CF1928122101867                         112.00      58.40E
$ awk '{printf "%06d%06d\n", $(NF-1)*100, $NF*100}' file1
011200005840
000000000000
000000000000
011200005840

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