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Accepting search pattern to script argument

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# 1  
Old 02-21-2012
Accepting search pattern to script argument
I have a script in tcsh and I want to have a find option to which I can pass a file search pattern I want using the command:

Code:
 /home/chrisd/tatsh/trunk/hstmy/bin/tcsh/raytrac.tcsh -f=*rc*

The set command seems to fail when user does not supply a search pattern (if user just supplies -f, a default search is performed).

Code:
 /home/chrisd/tatsh/trunk/hstmy/bin/tcsh/raytrac.tcsh -f


E.g. of the code:

Code:
/home/chrisd/tatsh/trunk/hstmy/bin/tcsh/raytrac.tcsh -f=*rc*

This is failing. I just want to get the *rc*
Code:
set arg_ierrLst = ""
set narg = $#argv
while ($iarg < $narg)

  MATH iarg = $iarg + 1
  set arg = $argv[$iarg]
  set opt = `echo $arg | awk 'BEGIN {FS="="} {print $1}' | tr '[:lower:]' '[:upper:]'`
  set par = `echo $arg | awk 'BEGIN {FS="="} {print $2}'`

  switch ($opt)

  case "-F":
  case "--FIND":
    set arg_findPtn = $par
    set opt_find = 1
    breaksw

  default:
    set arg_ierrLst = "$arg_ierrLst $arg"
    set ierr = 1
    breaksw

  endsw

end   # which

Last edited by kristinu; 02-21-2012 at 07:01 AM..
# 2  
Old 02-21-2012
ok i'm tcsh ignorant. forgive this post.
# 3  
Old 02-21-2012
I have written

Code:
set varq = "'$1'"
echo "varq = $varq"
set opt = `echo $varq | awk 'BEGIN {FS="="} {print $1}' | tr '[:lower:]' '[:upper:]'`
set par = `echo $varq | awk 'BEGIN {FS="="} {print $2}'`
echo "opt = $opt, par = $par"

Using the above piece of code and calling the program using:
Code:
/home/chrisd/tatsh/trunk/hstmy/bin/tcsh/test.tcsh '-f=*.com'

gives

Code:
varq = '-f=*.com'
echo: No match.
echo: No match.
opt = , par =

Seems echo is not liking it. Using cat instead of echo still gives same problem.

I have now tried

Code:
set arg = "'$argv[1]'"
set opt = `echo "$arg" | awk 'BEGIN {FS="="} {print $1}'`
set par = `echo "$arg" | awk 'BEGIN {FS="="} {print $2}'`
echo "arg = $arg, opt = $opt, par = $par"

and am getting

Code:
arg = '-f=*.com', opt = '-F, par = *.com'

Seems things are progressing now

The question I have now is how to remove the ' from arg.

I have tried
Code:
set arg = `echo "$arg" | tr '\'' ''`
 set arg = `echo "$arg" | awk '{gsub(/\'/,"")}; {print}'`

but neither of them worked.
Last edited by kristinu; 02-21-2012 at 01:47 PM..
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