Shell Programming and Scripting

Oh dear, I typed that too quickly:

Code:

dir_one="/usr/bin/sou"
dir_two="/usr/bin/sou/temp"
cd "$dir_one"
for file in *.jpg *.txt *.csv *.pdf *.gz
do
  mv "$file" "$dir_two"
done

hey thanks.while i am executing in script i am getting unexcepeted do error but while executing manually the above code it it working fine.so what ll be the issue while executing the same code pasting mv.sh can you please advise on it

If your script begins as it does in your original post, the script may not be using the shell you think it's using. The script file should begin with the #!path/to/shell line.

If that isn't the problem, provide the full script that you are using in an unambiguous form (using hexdump or od, for example). Also, tell us something about the environment you're working with. Which shell exactly? Which operating system?

Regards,
Alister

Further to alister, please post the script how it appears when processed through this "sed" command which is designed to make control codes visible.
It also shows a normal unix line terminator as a dollar sign. I notice from your post #1 that the script has a large amount of trailing space characters on some lines and I wonder if either this script is the product of a Microsoft editor or whether you have lines which have wrapped and are therefore missing the line terminator.

Code:

sed -n l mv.sh

Don't forget to post your Operating System and version and what Shell you are using.

Hi,

Try this one,

Code:

find /usr/bin/sou/ -name "*.txt" -o -name "*.csv" -exec  mv {} /usr/bin/sou/temp/ \;

Cheers,
Ranga

That will not work correctly due to operator precedence (the -exec only occurs when the basename matches *.csv).

Regards,
Alister

Code:

find /usr/bin/sou/ -name "*.txt" -o -name "*.csv" | xargs -I {} mv '{}' /usr/bin/sou/temp/

@alister: Thanks, Please elabrate the issue.

Cheers,
Ranga