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awk match function

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# 1  
Old 02-15-2012
Question awk match function
Hello,

I tried an example with 'match' and print out RSTART and RLENGTH.
Sadly it doesn't work.

Code:
test.txt >
yesterday was tuesday
today is wednesday
tomorrow is thursday

Code:
awk -F\\n '{ match( '/day/', $1 ); printf RSTART "," RLENGTH "\n" }' test.txt

output:
Code:
0,-1

# 2  
Old 02-15-2012
give a try to :
Code:
awk -F\\n '{ match($1,"day");printf RSTART "," RLENGTH "\n" }' text.txt

and (for education purpose) also give a try to:

Code:
awk -F\\n '{ match($1,"day");print substr($1,RSTART,RLENGTH),$2,$3}' text.txt

You can find the awk function's syntax here
Last edited by ctsgnb; 02-15-2012 at 08:46 AM..
# 3  
Old 02-15-2012
oh, thanx and sorry for this unnecessary question Smilie
# 4  
Old 02-15-2012
While we are at it. If we make FS equal to \n, while maintaining RS as is, we are effectively making $0 equal to $1. So the above statements should be equivalent to:
Code:
awk '{ match( $0, "day" ); print RSTART "," RLENGTH }' infile

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