Shell Programming and Scripting

Hi,
I have a folder with limited space. I do not have provisions to increase the space for this folder.
So i have to delete files which are more than 1 month old automatically.
But, i need to maintain the files created by 4 users and delete all the other files automatically which is more than 1 month.
So my script should be like i find all the files that do not belong to the 4 users and delete them if it is more than 1 month old.
Can someone help me to generate a script for this.
Regards,
Vivek

You could probably try something like the following. However be very wary of where you run this comman due to the "-f" option of the rm command.

cd destination_directory
rm -f `find * -mtime +30 | xargs ls -l | grep -v user1 | grep -v user2 | grep -v user3 | grep -v user4 | awk -F " " '{print $9}'`



jerardfjay

A little tidier:
Use with caution if running as root !!!

Code:

#!/bin/ksh
#
#removeFiles.sh
#
# Args $1 is the base directory to remove files from.
#

KEEPUSERS="user1|user2|user3|user4"

find ${1} -type f -mtime +30 -ls | egrep -v ${KEEPUSERS} | awk '{print $9}' | xargs rm -f

A little faster...

find . ! -user user1 ! -user user2 ! -user user3 ! -user user4 -mtime +30 | xargs rm -f

thank you so much...

with this post i learn the power of xargs....

i make an script and maybe could be useful for you...

it´s checks the size of the directory and if pass the limit, then check the oldest file and delete it...

This procces is in a loop.... when the spaces fit the limits that you previusly input, the scripts stops...

here is the code:


#bin/bash
#valor 0 es ok
#valor 1 es demasiado grande
. /arwebmin/variables/variables.conf
estado=0
LIMIT=1
limite=$syslogsize

while [ "$estado" -lt "$LIMIT" ]
do

size=`du $dir_incoming | cut -f 1`

echo "$size"
if [ $size -ge $espacio_maximo ] ; then
echo "es mayor"
echo "borrando: $dir_incoming$archivo"
ls -tb $dir_incoming | tail -1 | xargs rm -f

else
echo "es menor"
estado="1"

fi

done


---------------------------------

regards!.