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Use the print result of a script as an argument

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# 1  
Old 02-13-2012
Question Use the print result of a script as an argument
Hi all,

Say I have a script named script.sh. What it does is to print a line like "abc"
Code:
#! /usr/bin/ksh
 
print "abc"

I would like to pass this value to an external variable,

var1="script.sh"

However when I echo $var1 I got "script.sh" itself instead of the result?

Thanks
# 2  
Old 02-13-2012
use this one.
Quote:
var1=`./script.sh`
# 3  
Old 02-13-2012
Code:
$ echo 'echo "hello world"' > a.sh
$ chmod 755 a.sh 
$ var=$(a.sh)
$ echo $var
hello world

# 4  
Old 02-13-2012
Code:
var1=`ksh script.sh`

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