Shell Programming and Scripting

HI
My input is

12345678901234567890123456789012345678
pay 234 56789.23 7788934.5 2456
calcul 123 456 678 98
i want to print the line starting with "pay" as $2 should commence from 7 irresptive of its length and $3 to start from 14 and $4 to start from 24 and $5 from 36.
line starting with calcul is untouched and should print as it is($0)

Any way out fot these.

thnks nd regrds

Code:

$ perl -ane '(/^pay/) && printf ("%-6s%-7s%-10s%-12s%d", $F[0], $F[1], $F[2], $F[3], $F[4])' inputfile
pay   234    56789.23  7788934.5   2456

its not working for me....what about the line with calcul,its not getting printed out!!!
anything with awk or sed please

---------- Post updated at 11:21 PM ---------- Previous update was at 11:16 PM ----------

i have thousands of line starting with "pay"
pay 234 56789.23 7788934.5 2456
calcul 123 456 678 98
pay 234 56789.23 7788934.5 2456
calcul 123 456 678 98
etc etc

and the script prints all in a single line actually...
any way out plz..thanks a lot

Code:

perl -lane '(/^pay/)?printf ("%-6s%-7s%-10s%-12s%d\n", $F[0], $F[1], $F[2], $F[3], $F[4]):print' inputfile

Hi Balajesuri,
thanks alot