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how do i print literal value?

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# 1  
Old 02-06-2012
how do i print literal value?
hi guys!!!
i wanna print literal value itself.
for example,
mycommand=$( ls -ltr )
"echo $mycommand" is not working... it runs the "ls" command.
also "echo $"mycommand" " is not working either. it print out "mycommand" literally...
how can i print out " ls -ltr " using variable "mycommand"?
# 2  
Old 02-07-2012
Did you search the forum?
Code:
x='ls -lrt'

This User Gave Thanks to balajesuri For This Post:
curtis911
# 3  
Old 02-07-2012
yeah i searched, but couldnt find any.
it works!!! thank you!!!
but i want to set variable like x=$(l -ltr) and print value as string, can you do that?
Last edited by curtis911; 02-07-2012 at 04:41 AM..
# 4  
Old 02-07-2012
Anything in single-quotes will be considered literally.

Is this what you mean:
Code:
> x='$(ls -lrt)'
> echo $x
$(ls -lrt)

# 5  
Old 02-07-2012
Sorry, but unable to understand what you need?

Here are some conclusions in codes:

Code:
# x=$(ls -ltr)
# echo "$x"
total 20
-rw-r--r--  1 root root 58 Feb  7 12:29 data
-rw-r--r--  1 root root  0 Feb  7 13:51 script.sh
-rw-r--r--  1 root root  0 Feb  7 13:51 eon
-rw-r--r--  1 root root  0 Feb  7 13:51 bin.sh

# echo ${x}
total 20 -rw-r--r-- 1 root root 58 Feb 7 12:29 data -rw-r--r-- 1 root root 0 Feb 7 13:51 script.sh -rw-r--r-- 1 root root 0 Feb 7 13:51 eon -rw-r--r-- 1 root root 0 Feb 7 13:51 bin.sh

# x='ls -ltr'
# echo $x
ls -ltr
# echo "$x"
ls -ltr
# $x
total 20
-rw-r--r--  1 root root 58 Feb  7 12:29 data
-rw-r--r--  1 root root  0 Feb  7 13:51 script.sh
-rw-r--r--  1 root root  0 Feb  7 13:51 eon
-rw-r--r--  1 root root  0 Feb  7 13:51 bin.sh

---------- Post updated at 02:42 PM ---------- Previous update was at 02:38 PM ----------

Quote:
Originally Posted by curtis911
yeah i searched, but couldnt find any.
it works!!! thank you!!!
but i want to set variable like x=$(l -ltr) and print value as string, can you do that?
x=$(ls -ltr) : Through this construct, we pass the output of the command inside $() to the variable x. U can not pass the literal string via $() construct.

Or you can do one thing:

x=$(echo ls -ltr)

Code:
# x=$(echo ls -ltr)
# echo $x
ls -ltr
# $x
total 20
-rw-r--r--  1 root root 58 Feb  7 12:29 data
-rw-r--r--  1 root root  0 Feb  7 13:51 script.sh
-rw-r--r--  1 root root  0 Feb  7 13:51 eon
-rw-r--r--  1 root root  0 Feb  7 13:51 bin.sh

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