Shell Programming and Scripting

I have an array with characters, what I want is if there are other characters in the array which I am looking for than take action that is print BAD ARRAY. So far my code just finds characters but instead I want that it should look for other characters.

Code:

echo "A B C D F" | egrep -o "D | F"
O/P
D
F

I want a one liner that can look for characters other than D and F and if the array contains other characters than print Bad Array. That is I expect the array should have only D and F. In that case no action.
Thanks in adavance

There's lots of ways to do this, many of them slow, some of them less so. What's your system? What's your shell?

---------- Post updated at 10:22 AM ---------- Previous update was at 10:18 AM ----------

For BASH and newer ksh, you can do this:

Code:

if [[ ! -z "${STR//[AD ]/}" ]]
then 
        echo "Str contains the following non-AD chars:  ${STR//[AD ]/}"
fi

Thanks for your reply but my shell is tcsh.

You have my deepest condolences.

csh programming considered harmful

Code:

echo "$STR" | grep -v '[^AD ]' > /dev/null || echo "string contains non-AD"

That is funny but sometimes you are forced to use what is establish although my attempt is to create parallel scripts in Bash.

Code:

echo "A A D D" | grep -v '[^AD]' > /dev/null || echo "string contains non AD"
The expected output is:
nothing
but got
string contains non AD

I want: output as "string contains non AD" only when input is "A D E H"

Don't forget that I'm helping you anyway. It's no joke. If you're not being forced to use csh, you should count your blessings and run. Its inventor admits to "not being very good at programming when he wrote it", and its problems aren't bugs -- they're design flaws, unfixable. It really is that bad. Sooner or later you'll find out why by yourself.

My regular expression had a space in it, yours didn't. It's not optional -- that's the list of characters for it to accept and, without space, it doesn't accept spaces...