Shell Programming and Scripting

one problem. i executed SH script "sh common.sh".
then i opened another window and tried "jobs" command. But its not listing down any jobs. why ?

but, common.sh was still running.

How about

Lets say we have jobs named j1, j2, j3, j4 .... j10

In Cron Entry we have:

* * * * * touch /tmp/jobs/j1; j1 && rm -f /tmp/jobs/j1
* * * * * touch /tmp/jobs/j2; j2 && rm -f /tmp/jobs/j2
* * * * * touch /tmp/jobs/j3; j3 && rm -f /tmp/jobs/j3
...
...
...
* * * * * touch /tmp/jobs/j10; j10 && rm -f /tmp/jobs/j10

In nutshell, when the script will execute successfully, then the flag files (/tmp/jobs/j1, etc) will get deleted.

Now the monitoring tool/script can have:

Code:

 
while [ 1 ]; do
    if [[ ! -f /tmp/jobs/j1 && ! -f /tmp/jobs/j2 && ! -f /tmp/jobs/j3 && ! -f /tmp/jobs/j4 && ! -f /tmp/jobs/j10 ]]; then
            break;
    else
            sleep 5
            continue
    fi
done

The "jobs" command refers to background jobs running on the current terminal session. You did not background "common.sh" (with an & command) and therefore it ran in foreground.
Looking at "jobs" in another terminal window is irrelvant.