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Passing Array to awk

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# 1  
Old 01-26-2012
Passing Array to awk
I'm trying to use the following command:

Code:
awk -v array1=${array1[@]} -f "filename.awk" input.txt

Then within filename.awk I want to access array1[n]. However, awk mistakes array1[2] (the third element of the array) for the input file. How I can pass awk this array?

It also appears that awk scripts can't understand ":-" or ${#var}. Is this correct?
# 2  
Old 01-26-2012
Code:
awk -v array1="${array1[*]}" -f "filename.awk" input.txt

Inside filename.awk

Code:
BEGIN{ split(array1,arr," "); print arr[1]}

--ahamed
# 3  
Old 01-26-2012
Quote:
Originally Posted by B-Ry
It also appears that awk scripts can't understand ":-" or ${#var}. Is this correct?
awk is entirely its own programming language with its own variables that have nothing to do with the shell's. -v arguments are where shell variables and awk variables meet, to get them into awk you pass them in there as raw text.
# 4  
Old 01-26-2012
Awesome, thanks!
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