Shell Programming and Scripting

I was trying to do some experiment with "sed".

I want to find the filenames which are three characters. So, this is what I have done to search for it, using sed.

Code:

sed -n -e '/^[a-z]\{3\}$/p' test

This returns the correct output for characters. But if I make change, let's say i create 2 more files 123 and 456. I cannot get the output that i wish to see with this command:

Code:

sed -n -e '/^[a-z]\{3\}$/,/^[0-9]\{3\}$/p' test.

even this does not work :

Code:

sed -n -e '/^[*]\{3\}$/p' test

All in all..it fails when I have numbers.. Is something wrong with the syntax?
I want to find all the files which are 3 characters long??

Moderator's Comments:

Please use next time code tags for your code and data

You mean sth like that? :

Code:

sed -n -e '/^[a-z0-9]\{3\}$/p' test

or even:

Code:

sed -n -e '/^.\{3\}$/p' test

Wouldn't this suffice?

Code:

ls -1 | egrep "^.{3}$"

I didn't understand. Are you looking for files with 3 character long names or are you looking for strings in a file 'test' which are 3 characters long?

If it's files in the current directory tree:

Code:

find . -type f -name \?\?\? -print

Thanks for the reply..
Sorry... I wasn't that clear. I was not looking for files. Was looking for characters, and wanted to know about sed...