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print only the first occurrence of a pattern

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# 1  
Old 01-17-2012
print only the first occurrence of a pattern
Hi,
I have a file as below

Code:
select or create proc
/*comments*/
/*comments*/
/*comments*/
/*comments*/
( variables4 datatypes1,
variables1 datatypes2,
variables2 datatypes3,
variables3 datatypes2
)
 
 
some text some text
(
sometext some text
)
some text some text
(
sometext some text
)

Output :-
Code:
variables4 datatypes1,
variables1 datatypes2,
variables2 datatypes3,
variables3 datatypes2

we should search for the first occurrence of ( and ) and print the text inside it.
Last edited by radoulov; 01-17-2012 at 08:01 AM.. Reason: Please use code tags!
# 2  
Old 01-17-2012
Code:
 
$ nawk -F"[()]" 'BEGIN{RS=""}{print $2;exit}' input.txt
variables4 datatypes1,
variables1 datatypes2,
variables2 datatypes3,
variables3 datatypes2

This User Gave Thanks to itkamaraj For This Post:
manasa_vs
# 3  
Old 01-17-2012
Just a try ..
Code:
$ sed -n '/)/q;p' infile | sed -n '/(/,$p'

# 4  
Old 01-17-2012
thanks its worked :)
Quote:
Originally Posted by itkamaraj
Code:
 
$ nawk -F"[()]" 'BEGIN{RS=""}{print $2;exit}' input.txt
variables4 datatypes1,
variables1 datatypes2,
variables2 datatypes3,
variables3 datatypes2

thanks its worked SmilieSmilie
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