search for a pattern using awk between two words


 
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# 8  
Old 01-16-2012
Quote:
Originally Posted by Scrutinizer
Found it. I had true and false reversed:
Code:
awk '{sub(/$/,RS)} /select/{s=/\(\)/?"false":"true";sub(/$/,"-->"s)}1' RS=\; infile

it still has problem
select some text
(select some text(select some text)
where some condition)
where condition;-->false;
select cl,c2,c3,c4,fn(),c5-->false;
select c1,c2,c3-->true;

for the first select it should be true.
for 2nd and 3rd statement its correct.
# 9  
Old 01-16-2012
With this input file:

Code:
select some text
(select some text(select some text)
where some condition)
where condition;
select cl,c2,c3,c4,fn(),c5;
select c1,c2,c3;

and using this:
Code:
awk '{sub(/$/,RS)} /select/{s=/\(\)/?"false":"true";sub(/$/,"-->"s)}1' RS=\; infile

I get:

Code:
select some text
(select some text(select some text)
where some condition)
where condition;-->true
select cl,c2,c3,c4,fn(),c5;-->false
select c1,c2,c3;-->true
;

Is this not what you are getting?
Are you using Solaris?

Last edited by Scrutinizer; 01-16-2012 at 03:46 AM..
This User Gave Thanks to Scrutinizer For This Post:
# 10  
Old 01-16-2012
its working...but one more additation

Can we print only the false statements than printing all the other statements and true statements?
# 11  
Old 01-16-2012
Do you mean like this?
Code:
awk '/select/ && /\(\)/'  RS=\; ORS=\; infile

# 12  
Old 01-16-2012
Yes Smilie
Thanks.
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