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Script for deleting files and directories when the file system reaches the threshold

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# 1  
Old 01-12-2012
Script for deleting files and directories when the file system reaches the threshold
Hi

Can someone assist in writing a script.
I have a filesystem named /sybase in my aix lpar.
When this filesystem becomes 94% full all the files and directories under /sybase/logs should be deleted immediately. Smilie
# 2  
Old 01-12-2012
This should do the trick:

Code:
#!/bin/bash
use=`df | grep /sybase | awk '{print $(NF-1)}'`   #get the percentage use 
use=${use%*%}  #get rid of the trailing '%'
if [ $use -gt 94 ] ; then
    rm -r /sybase/logs/*
fi

This script should be run by cron as often, as you think is necessary (every hour, day?). If you want it to run every hour, just copy it into /etc/cron.hourly, if that exists on your system. If not, then make an entry in the crontab. Make sure the script is executable.
This User Gave Thanks to mirni For This Post:
newtoaixos
# 3  
Old 01-12-2012
one liner ..
Code:
$ df -h /sybase | nawk '/%/{sub(/%/,"");if($5>=94)print "rm -r /sybase/logs/*" }' | sh

This User Gave Thanks to jayan_jay For This Post:
newtoaixos
# 4  
Old 01-16-2012
Hi Jayan Jay
The command you have given works fine. Thank you so much
@ Mirni : I saved the content you gave as script.ksh
When I execute it gives the below error:
Code:
cbspssit01:/ # ksh /scripts/script.ksh
/scripts/script.ksh[4]: 1%: more tokens expected

# 5  
Old 01-17-2012
Quote:
Originally Posted by newtoaixos
Hi Jayan Jay
The command you have given works fine.
Actually, jayan's one liner may not work correctly on some systems -- it may clear the directory tree even if the use is low. With GNU df, the header contains '%' sign and so you have two lines there:
Code:
Filesystem            Size  Used Avail Use% Mounted on
/dev/sda7              32G   24G  5.8G  81% /sybase

Awk in jayan's command will process both of these lines. Regardless of the use% in the second line (the actual record), the first line will always be matched. That's because the fifth field of the first line, stripped of the '%', will satisfy the if condition:
Code:
"Use" > 94

is always true in awk's language. That is because the integer 94 is automatically converted to a string, and then compared to "Use".

As for my code, it seems that the variable 'use' is empty. Try to echo 'use' variable before the if statement. What does this print?
Code:
df | grep /sybase

Last edited by mirni; 01-17-2012 at 09:27 AM.. Reason: removed offensive word "bug"
# 6  
Old 01-17-2012
@mirni, i am using SunOS 5.9 and when firing df -h , it wont show Use% in fifth column ..
Code:
$ df -h /
Filesystem                    size  used   avail capacity  Mounted on
/dev/vx/dsk/bootdg/rootvol    9.8G   7.8G   1.9G    81%    /

Hence the header of df -h might vary from OS to OS and dont come to a conclusion that the one liner has a bug .. Smilie

If your OS doesnt support that feature, below is the one liner will suit your match. Smilie
Code:
$ df -h /sybase | nawk '/sybase/{if(int($5)>=94){print "rm /sybase/logs/*"}}' | sh

One more in nawk ..
Code:
$ df -h /sybase | nawk '/sybase/{sub(/%/,"");if($5>=94)print "rm -r /sybase/logs/*" }' | sh

# 7  
Old 01-17-2012
I didn't mean to offend you -- I appreciate you being here helping others. I only wanted to point out a potential pitfall. Although it may work with your version of df (and perhaps the OP's also), it didn't with mine on GNU/Linux system.
Code:
df (GNU coreutils) 8.5

Remember there may be many people viewing this post trying to find a solution to their problem on their variety of *nix platforms...
I reformulated my previous post a little bit.
Peace,
mirni
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