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Using awk array problem

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# 1  
Old 01-11-2012
Using awk array problem
I am trying to map values in the input file, where 2nd column depends on the specific value in the 1st column. When 1st column is A place 1 into 2nd column, when it is B, place 2, when C place 3, otherwise no change.

My input:
Code:
U |100|MAIN ST   |CLMN1|1
A |200|GREEN LN  |CLMN2|2
1 |12 |THIRD ST  |CLMN3|3

Intended output:
Code:
U |100|MAIN ST   |CLMN1|1
A |1|GREEN LN  |CLMN2|2
1 |12 |THIRD ST  |CLMN3|3


My code:
Code:
gawk -F'|' '
BEGIN{
        map["A"] = 1;
        map["B"] = 2;
        map["C"] = 3;
        OFS = "|";
}
{
        s = "not found"
        if ($1 in map) {
                $2 = map[$1];
                s = "Found:" $1 " : " map[$1];
        }
        print $0, s;
}
END{
        OFS = ":";
        print "Just checking my array:"
        for (a in map) { print a, map[a] }
}
'

The problem is, letter "A" in the 2nd row is not found in the array somehow.
I added printing my map array out and 'found/not found' to check myself, nothing is found.
The output:

Code:
 
U |100|MAIN ST   |CLMN1|1|not found
A |200|GREEN LN  |CLMN2|2|not found
1 |12 |THIRD ST  |CLMN3|3|not found
Just checking my array:
A:1
B:2
C:3

Any ideas what I do wrong?

Just a note: there are many ways to do it, I'd like to keep present way of mapping values initialized in the array, there might be a possibility for untrained people to mainain the mapping in the future.
# 2  
Old 01-11-2012
Because the value you have in field 1 is "A " not "A"
This User Gave Thanks to Chubler_XL For This Post:
migurus
# 3  
Old 01-11-2012
Code:
[root@node2 ~]# cat get 
awk -F'|' '{
            if($1 ~ /A/)
               $2=1
            if($1 ~ /B/)
               $2=2
            if($1 ~ /C/)
               $2=3
            OFS="|"
            print $0
           }' $1

              
[root@node2 ~]# bash get data 
U |100|MAIN ST   |CLMN1|1
A |1|GREEN LN  |CLMN2|2
1 |12 |THIRD ST  |CLMN3|3
B |2|core  ST  |CLMN3|4
C |3|THIRD ST  |CLMN3|3
[root@node2 ~]# cat data 
U |100|MAIN ST   |CLMN1|1
A |200|GREEN LN  |CLMN2|2
1 |12 |THIRD ST  |CLMN3|3
B |800|core  ST  |CLMN3|4
C |12 |THIRD ST  |CLMN3|3

# 4  
Old 01-11-2012
As I said in my note: I am looking for a solution where the mapping is not in the code, but rather in the array in the BEGIN section, so other people who do not know awk would be able to easy change the mapping.
# 5  
Old 01-12-2012
You already got an answer from ChublerXL, it is because $1 is "A " not "A". If you want to keep your present code, I suggest you preprocess your data to not contain spaces before or after the pipe delimiter:
Code:
sed 's/ *| */|/g' dataFile | awk '{...

Actually, there is a more elegant way; just set the delimiter to " *| *" instead of "|". That way it will eat the spaces.
Code:
 awk -F =" *| *" '{...

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