do you have a better way to set this variable?


 
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# 1  
Old 01-05-2012
do you have a better way to set this variable?

greetings,

i have a variable $input that i want to use to set $output. $input is /dir/filename.mph and $input is passed to my script that i manipulate it as follows:

Code:
input=`basename $input`

i want the $output to be filename_solved.mph, basically stuffing "_solved" in the filename. here's how i did it:

Code:
output=`echo $input | awk -F. '{print $1}'`_solved.mph

more informational than anything, but was wondering if there's a more "streamline" way of doing it?
# 2  
Old 01-05-2012
Code:
input=/dir/filename.mph
input=${input##*/}
output=${input%.*}_solved.mph

Code:
$ echo -e "input=$input\noutput=$output"
input=filename.mph
output=filename_solved.mph


Last edited by ctsgnb; 01-05-2012 at 02:15 PM..
This User Gave Thanks to ctsgnb For This Post:
# 3  
Old 01-05-2012
nice!
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