File that Contains a List of Files


 
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# 1  
Old 12-29-2011
File that Contains a List of Files

I have a first text file (LoopFiles.txt) that contains another list of text files. I need to run NAWK commands on each of the files that are listed in the first text file.

I have proven the existence of the first file with ls -l

But I get a message that my first file doesnt exist.
Code:
cd /tmp/Me/
 
while getline x < f; f="/tmp/Me/LoopFiles.txt"
do
nawk -F, '{if($2==$5){a[$2]++}}END{for(i in a){print i"\t"a[i]}}' x
done
 
[btsadm@anhmcabts01]$bash rcc_guineapig_3.sh
2011 12 28
rcc_guineapig_3.sh: f: No such file or directory

The nawk command is to be used to compare column #2 and column #5 to see if they match, and if so, peg a counter for the value in column 2, and print the value and number of pegs for each value in column 2. That has to be done on each file listed in LoopFiles.txt.

Last edited by radoulov; 12-29-2011 at 06:39 PM.. Reason: Code tags!
# 2  
Old 12-29-2011
It exists somewhere else. after you cd, you're no longer in that somewhere else.
# 3  
Old 12-29-2011
To paraphrase Corona :

LoopFiles.txt has to contain files names that look like this:
Code:
/path/to/textfile.txt
/another/path/to/anotherfile.txt

# 4  
Old 12-29-2011
Untested.

Code:
f="tmp/Me/LoopFiles.txt"
while read x
do
    echo $x | nawk -F, '{if($2==$5){a[$2]++}}END{for(i in a){print i"\t"a[i]}}'
done < $f

# 5  
Old 12-29-2011
Code:
 
cd /tmp/Me/
f="/tmp/Me/LoopFiles.txt"
while getline x
do
nawk -F, '{if($2==$5){a[$2]++}}END{for(i in a){print i"\t"a[i]}}' $x
done < f

[btsadm@anhmcabts01]$bash rcc_guineapig_3.sh
2011 12 28
rcc_guineapig_3.sh: f: No such file or directory

---------- Post updated at 08:57 AM ---------- Previous update was at 08:56 AM ----------

Quote:
Originally Posted by balajesuri
Untested.

Code:
f="tmp/Me/LoopFiles.txt"
while read x
do
    echo $x | nawk -F, '{if($2==$5){a[$2]++}}END{for(i in a){print i"\t"a[i]}}'
done < $f

i think, its not
HTML Code:
echo $x
 
it should be
 
nawk -F, '{if($2==$5){a[$2]++}}END{for(i in a){print i"\t"a[i]}}' $x
# 6  
Old 12-30-2011
That worked, balajesuri.

Thanks so much!
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