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printf before execl system call

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# 1  
Old 12-28-2011
printf before execl system call
Code:
main()
{
printf("before execl");
execl("/home/nirmala/os/fact","fact");
printf("this line will not be printed");
}


for the above program ,the obj file of fact.c is getting loaded correctly.am getting the output as...
Code:
factorial =6

but in ouput am not getting the string given in printf(1st printf) function.why is it so?

please do help me.am trying for one week.am not getting the reason.

thanks in advance.
Last edited by Franklin52; 12-29-2011 at 10:33 AM.. Reason: Please use code tags for data and code samples, thank you
# 2  
Old 12-28-2011
1. printf's are buffered, try giving a fflush(stdout) after the printf
2. 2nd printf will not print for obvious reason i.e. execl will replace the current process image with a new one.

It is always good to have a return value for the main().

HTH
--ahamed

PS : Wrong thread to post C/C++ questions. Mod's might move it.
This User Gave Thanks to ahamed101 For This Post:
pnirmala
# 3  
Old 01-03-2012
thanks a lot ahamedSmiliei got the correct one.Smilie
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