removing a range of characters in a filename


 
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# 1  
Old 12-28-2011
removing a range of characters in a filename

hi, I have quite a bunch of files with annoyingly long filenames. I wanted to cut the range of characters from 9-18 and just retain the first 8 characters and the .extension. any suggestion how to do it. thanks much.

Code:
original filename: 20000105_20000105_20100503.nc.asc
output filename: 20000105.asc

# 2  
Old 12-28-2011
Code:
for x in `ls *.nc.asc`; do mv $x `echo $x|cut -d_ -f2`.asc; done

This User Gave Thanks to balajesuri For This Post:
# 3  
Old 12-28-2011
Code:
 
for i in *.nc.asc; do echo mv $i ${i%%_*}.${i##*.}; done

execute the above command and make sure it gives the correct mv command ouput.

If you are satisified then, remove the echo commmand and run it
This User Gave Thanks to itkamaraj For This Post:
# 4  
Old 12-28-2011
thanks a lot guys for the quick replies,Smilie
# 5  
Old 12-28-2011
one more .. Smilie
Code:
$ ls -1 *.nc.asc | nawk -F. '{print "mv "$0" "substr($1,1,8)"."$NF}' | sh

This User Gave Thanks to jayan_jay For This Post:
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