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Help with replace the content of specific pattern

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# 1  
Old 12-14-2011
Help with replace the content of specific pattern
Input file:
Code:
__<name>AWEETET</name>
____<name_evidence="3"_type="2@#">QEWQE</name>
__<name>QWE048</name>
____<name_evidence="3"_type="570">@#@$#545</name>
____<name_evidence="2"_type="351">QWE4</name>

Desired output:
Code:
__<tmp>AWEETET</tmp>
____<name_evidence="3"_type="2@#">QEWQE</name>
__<tmp>QWE048</tmp>
____<name_evidence="3"_type="570">@#@$#545</name>
____<name_evidence="2"_type="351">QWE4</name>

Command that I tried:
Code:
[home@perl_beginner]sed 's/^__<name>[a-z]*[0-9]*<\/name>/^__<tmp>[a-z]*[0-9]*<\/tmp>/g' input_file.txt

Thanks for any advice.
# 2  
Old 12-14-2011
In your replacement you cannot use expressions such as .* or [0-9]. You need to put parentheses round the portion(s) of the pattern that you wish to "copy into the replacement string when the pattern is matched. Back references (\1 in this case) are used in the replacement to show where the contents of the portion of the string that matched inside of the parentheses are to be copied.

Given that, this might work:
Code:
sed  's/^__<name>\(.*\)<\/name>/__<tmp>\1<\/tmp>/' data-file

# 3  
Old 12-15-2011
Quote:
Originally Posted by perl_beginner
Command that I tried:
Code:
[home@perl_beginner]sed 's/^__<name>[a-z]*[0-9]*<\/name>/^__<tmp>[a-z]*[0-9]*<\/tmp>/g' input_file.txt

Additionally, words following <name> are in UPPER case, the above highlighted would match the lower cases only and [a-z]*[0-9]* sequence tells that zero or more occurrences of alphabets followed by zero or more occurrences of numeric, which may sometimes fail if the word is an alpha-numeric as in QWE048TRR. This could be rectified by giving the regex as [A-Z0-9]*
Code:
sed 's/__<name>\([A-Z0-9]*\)<\/name>/__<tmp>\1<\/tmp>/' inputfile

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