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need a df -h oneliner..

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Top Forums Shell Programming and Scripting need a df -h oneliner..
# 1  
Old 12-08-2011
need a df -h oneliner..
can any one suggest some one liner such that when executed will display df -h output of the mount points that are 90% or more that it.. and not the remaining..
# 2  
Old 12-08-2011
Code:
 
df -h | grep "9[0-9]%"

These 2 Users Gave Thanks to itkamaraj For This Post:
chidori sdebasis
# 3  
Old 12-08-2011
wowwwww
wow.. Thanks.. i was thinking about logics , scripts.. silly me.. i forgot the sweet little tool called grep Smilie Thanks ..

---------- Post updated at 05:27 AM ---------- Previous update was at 04:50 AM ----------
i found one more way!!!


Code:
df -h | awk '$5>=70{print}'

df -h output
Code:
# df -h
Filesystem             size   used  avail capacity  Mounted on
/dev/dsk/c0d0s0        4.6G   3.6G  1020M    79%    /
/devices                 0K     0K     0K     0%    /devices
ctfs                     0K     0K     0K     0%    /system/contract
proc                     0K     0K     0K     0%    /proc
mnttab                   0K     0K     0K     0%    /etc/mnttab
swap                   576M   924K   575M     1%    /etc/svc/volatile
objfs                    0K     0K     0K     0%    /system/object
sharefs                  0K     0K     0K     0%    /etc/dfs/sharetab
/usr/lib/libc/libc_hwcap1.so.1
                       4.6G   3.6G  1020M    79%    /lib/libc.so.1
fd                       0K     0K     0K     0%    /dev/fd
swap                   575M    84K   575M     1%    /tmp
swap                   575M    40K   575M     1%    /var/run
/hgfs                   16G   4.0M    16G     1%    /hgfs
tank                   464M    18K   464M     1%    /tank
#

using grep command
Code:
# df -h | grep "7[0-9]%"
/dev/dsk/c0d0s0        4.6G   3.6G  1020M    79%    /
/usr/lib/libc/libc_hwcap1.so.1   4.6G   3.6G  1020M    79%    /lib/libc.so.1

using AWK command
Code:
# df -h | awk '$5>=70{print}'
Filesystem             size   used  avail capacity  Mounted on
/dev/dsk/c0d0s0        4.6G   3.6G  1020M    79%    /
/usr/lib/libc/libc_hwcap1.so.1   4.6G   3.6G  1020M    79%    /lib/libc.so.1

well , when using awk the header field is not omitted
Code:
Filesystem             size   used  avail capacity  Mounted on

# 4  
Old 12-08-2011
Code:
nawk 'NR>1 && $5>=70' inputfile.txt

# 5  
Old 12-08-2011
cool.. there is always another way :)
can you please explain about the nawk command you pasted.. i am not familiar with nawk
# 6  
Old 12-08-2011
NAWK stands for “New AWK”. This is AT&T’s version of the Awk

we have one more awk. ie..
GAWK stands for “GNU AWK”. All Linux distributions comes with GAWK. This is fully compatible with AWK and NAWK.

instead of nawk, you can try with awk also.

AWK Vs NAWK Vs GAWK (link removed)
# 7  
Old 12-09-2011
a tweak needed :(
the ouput of this one liner has gone little out of format..
Code:
# df -h | awk '$5>=70{print}'
Filesystem             size   used  avail capacity  Mounted on
/dev/dsk/c0d0s0        4.6G   3.6G  1020M    79%    /
/usr/lib/libc/libc_hwcap1.so.1   4.6G   3.6G  1020M    79%    /lib/libc.so.1

see the below normal output of df -h which has the even spacing..

Code:
# df -h / /lib/libc.so.1
Filesystem             size   used  avail capacity  Mounted on
/dev/dsk/c0d0s0        4.6G   3.6G  1020M    79%    /
/dev/dsk/c0d0s0        4.6G   3.6G  1020M    79%    /
#

is there anyway i can get the output in the same format ?

i figured out one way.. but i feel there would a better and cleaner way
Code:
# df -h | awk '$5>=70{print}' | awk '{print $6}' | xargs df -h 2>/dev/null

please help me out..

---------- Post updated 12-09-11 at 04:13 AM ---------- Previous update was 12-08-11 at 10:18 AM ----------

Code:
df -h | awk '{if($5>=70&&NR!=1){print $6}}' | xargs df -h

The previous code printed the heading 'Mounted' followed by the mount point names.. that is the reason it was throwing error. Now the above pasted code works fine Smilie

But would be eager to know if there is another way for this
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