I am really newbie of csh and I am stuck with a script.
Basically what I want to do is assign to a variable (array) the output of "ls". Then look at this array and if there is the word "my_file", delete it from the array and echo the new array.
Moreover, I would like to have that every single item of my array is the input of a program.
Well I am stuck with both things. This is what I thought:
Code:
#!/bin/csh
set list=`ls *.img`
echo -n "Name of your final dataset:"
set y = $myfile (the item that I want to remove from the array)
foreach i ($list)
if ($i =~ $y) then
unset ${list[$i]}
echo $list
/my_program <<EOF
$i
data
EOF
endif
I don't know how to find the index of an item in the list and delete exactly that item.
Please help...
Thanks guys.
Last edited by fpmurphy; 12-05-2011 at 10:59 AM..
Reason: Code tags please!
echo -n "Name of your final dataset:"
set my_dataset=$<
set A=`grep -vl $my_dataset $list`
echo "Appending:" $A
echo "Number of file:" $#A
foreach i ($A)
/append.e <<EOF
$i
$my_dataset
EOF
end
/headers.e <<EOF
HY
$my_dataset
EOF
# ./justdoit_cs1
LIST -> a.img b.img c.img d.img e.img
Name of your final dataset: c.img
NEW LIST -> a.img b.img d.img e.img
Code:
# cat justdoit_cs1
#!/bin/csh
set list=`ls *.img`
echo LIST " -> $list"
echo -n "Name of your final dataset: "
set y = $<
set x = 0
foreach i ($list)
@ x++
if ("$i" == "$y") then
set list[$x] =
set list = `echo $list`
endif
end
echo NEW LIST "$list"
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