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Script to display a dialog box every 5 seconds

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# 1  
Old 12-05-2011
Script to display a dialog box every 5 seconds
I want to create a script that displays a dialog box every interval of time and exits that loop when a user presses ENTER

Any idies?
# 2  
Old 12-05-2011
What have you tried so far?
# 3  
Old 12-05-2011
Code:

Code:
while :
  do
     echo 'Please Wait'

sleep 5
clear
done

# 4  
Old 12-05-2011
Here is a thread discussing how to capture a single key stroke:
https://www.unix.com/unix-dummies-que...ser-input.html
# 5  
Old 12-05-2011
try this Smilie
Code:
#!/bin/bash
while :;do timeout=10
echo -ne "Please give a input \033[1m'PRESS ENTER for EXIT'\033[0m\n? ";read -r c
if [[ "$c" == $'\0' ]] ; then break ; exit 1; fi
for((i=1;i<=$timeout;i++)); do
echo -e "Waiting for...`sleep 1`\E[0;31;40m[$(($timeout-$i))]\033[0m "
done;done

regards
ygemici
This User Gave Thanks to ygemici For This Post:
amitlib
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