Shell Programming and Scripting

Code:

 
find . -type f -mtime -1 -maxdepth 1

i am using sh shell

---------- Post updated at 05:57 AM ---------- Previous update was at 05:55 AM ----------

maxdepth does not work for me
find . -type f -mtime -1 -maxdepth 1
find: bad option -maxdepth
find: path-list predicate-list

Code:

ls -l | perl -ne '$x=substr localtime, 4, 6; /$x/ && print $_'

this is displaying 2010 files also

-rw-r----- 1 ajay ajay 0 Dec 2 20:37 test11.txt
-rw-r----- 1 ajay ajay 0 Dec 2 20:32 test1.txt
-rw-r----- 1 ajay ajay 0 Dec 2 20:32 test.txt
-rw-r----- 1 ajay ajay 0 Dec 2 20:37 text12.txt
-rw-r----- 1 ajay ajay 0 Dec 2 2010 text20.txt
-rw-r----- 1 ajay ajay 0 Dec 2 2010 text21.txt
-rw-r----- 1 ajay ajay 0 Dec 2 2010 text22.txt
-rw-r----- 1 ajay ajay 0 Dec 2 2010 text23.txt
-rw-r----- 1 ajay ajay 0 Dec 2 20:32 text3.txt
-rw-r----- 1 ajay ajay 0 Dec 2 20:32 text4.txt

Code:

ls -ltrh | egrep "`date | cut -c5-10`.*:"

Works for me on a SunOS 5.9 system

Code:

ls -l | perl -ne '$x=substr localtime, 4, 6; /$x\s+[0-9]{2}:[0-9]{2}/ && print $_'

Thanks CarloM this is working fine ...will it work at my OS always ...irrespective of if there exists 2009 , 2008 files at dir ...thanks again ,..can u please explain cut -c5-10`.*:" part
---------- Post updated at 06:16 AM ---------- Previous update was at 06:09 AM ----------

CarloM,
One more help required ..if there is no file found for today then I would like to display
"No files for today" ...how to check that condition...