Shell script that lists files with different owner than the folder


 
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# 8  
Old 11-26-2011
@ahamed101:

A thank you is on it's way, but I think I got logged out from the site before I posted it, and now a moderator has to approve it. :-)

Your last code worked, just as it should be, thank you for the easy solution! Smilie

I tried however with the code I posted earlier, and it seems, that that one works too. It uses the actual username, not to foldername, so I think it's prettier. I also added a
Code:
-type f

option to 'find', because the previous solution included folders too.

So, here is the finished code, what do you think about it? Any mistakes, that I should have seen?

Code:
#!/bin/bash

cd /home
DIR=$( ls -l | awk '{print $3}' )

for dir in $DIR
do
  user=$( basename $dir )
  find $dir ! -user $user -type f -exec echo "{}" is not owned by $user \;
done

And again: thank you for the help! :-)
# 9  
Old 11-27-2011
DIR=$( ls -l | awk '{print $3}' ) this will give you the user's right?... Shouldn't it be DIR=$( ls -d /home/* )?

--ahamed
# 10  
Old 11-27-2011
Code:
DIR=$( ls -l | awk '{print $3}' )

will return the name of the owner for every item in the folder, while your solution returns the list of folders. They are pretty much the same, but if we want to check owners, I think mine is safer.
# 11  
Old 11-27-2011
In that case, which directories will you search?

My solution gets the directory list and then extracts the user and does a find (provided all the user home directory has the the username in it). I think what you want is the the script which you mentioned as complicated, that does the job you want!

--ahamed
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