Shell Programming and Scripting

I have a file in which I need to find every occurance of PASSWORD="somepassword" and replace the actual password with "xxx". Within the file that I am working, I can have combinations of PASSWORD or it can also show as RMT_PASSWORD. The 'edited' file (with passwords x'ed out) will then be emailed as file attachments. Is sed the right tool to use here? Can someone possibly give me an example?


Thanks in advance!

sed 's/PASSWORD=".*"/PASSWORD="xxx"/'

You can use sed to make this as,

# echo "PASSWORD="somepassword"" | sed 's/PASSWORD=.*/PASSWORD="xxx"/'
PASSWORD="xxx"

To simply text format and save the same contents then use PERL as,
# echo "PASSWORD="somepassword"" | perl -pi -e 's/PASSWORD=.*/PASSWORD="xxx"/'
PASSWORD="xxx"

HTH.

hey guys thanks for the help!

For PASSWORD="123456" and RMT_PASSWORD="abc123" it works great. I can also get variations where I space on either side of the "=" sign. Example:

PASSWORD= "abc"
PASSWORD ="abc"
PASSWORD = "abc"

Is there an easier way to accomodate these than my idea which is to have 3 additional sed statements to account for these? (I'm sure there is).

Thanks in advance!!

sed 's/PASSWORD[ ]*=[ ]*".*"/PASSWORD="xxx"/'

will replace the password including zero or more spaces around the "="