Don't understand AWK asort behaviour

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# 1  
PHP Don't understand AWK asort behaviour


I have the following script :

print "1 ***";
  for (i in T) printf("%i:%s ",i,T[i]);  print "";
  for (i=1; i<=length(T); i++) printf(T[i]); print ""

print "2 ***";
  for (i in U) printf("%i:%s ",i,U[i]);  print "";
  for (i=1; i<=length(U); i++) printf(U[i]); print ""

and I don't understand the line following 2*** in the resulting display :

$ awk -f tst
1 ***
26:z 5:e 1:a 2:b 25:y 3:c 
2 ***
26:z 17: 4: 18: 5: 19: 6: 7: 8: 9: 10: 20: 11: 21:a 12: 22:b 13: 23:c 14: 1: 24:e 15: 2: 25:y 16: 3: 

I thought the result should have been : 1:a 2:b 3:c 4:e 5:y 6:z.

Where I am wrong ?
# 2  
for (i=1; i<=length(T); i++) printf(T[i]);

caused the array T to be filled with many null values. At the beginning, length(T) was 6. When i was incremented to 4, it created new array element T[4], etc.
This User Gave Thanks to binlib For This Post:
# 3  
In AWK, arrays are associative and array subscripts are always strings. Arrays can be sparse as in your example. If you use an array subscript (expression index) to refer to an array element that has no recorded value, i.e. T[10], then the value returned is "", the null string.

You can test whether a particular index exists, without the side effect of creating that element if it is not already present by using an
index in array


For more information, see Chapter 11 of Effective AWK Programming by Arnold Robbins.
This User Gave Thanks to fpmurphy For This Post:
# 4  
Hi all,


Last edited by jgilot; 11-24-2011 at 08:31 AM.. Reason: I self responded my question.
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