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awk length of digit and print at most right digit

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Top Forums Shell Programming and Scripting awk length of digit and print at most right digit
# 8  
Old 11-23-2011
Try this...
Code:
awk '/^[0-9]/{match($0,"([0-9]*[; ]*[a-zA-Z].*)",a); $0=a[1]}1' input_file

--ahamed
This User Gave Thanks to ahamed101 For This Post:
sdf
# 9  
Old 11-23-2011
Quote:
Originally Posted by forroughuse
Hi ygemici,

Nice Smilie

Code:
$ sed '1~2s/.* \([^ ]* [^ ]* [^ ]* [^ ]*\)/\1/'

Can you please explain me how it works/run.
1~2p says to SED that work on every 2nd line starting from 1. line..
so skip/ignore 2-4-6...lines and works other lines..
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