Shell Programming and Scripting

Hi, since half an hour I currently try to write a script that will:
1) Extract every debian file in a directory
2) Extracts it to a folder that matches the debians filename
3) Extracts it so the structure looks like that:

DEBIANFILENAME
|
-------------- DEBIAN
|
-------------- DEBIANDATA (Applications, whatever)

to achieve this I used that:

Code:

dpkg -x *.deb DEBIANFILENAME
dpkg -e *.deb DEBIANFILENAME
mv DEBIAN DEBIANFILENAME
sudo chmod -R 755 DEBIANFILENAME

however this doesn't:
- extract multiple debians
- only works with one debian a time
- doesn't create folders that match the previous debian filename

I would need it to read the filename of each debian as a variable, then feeding it into the script instead of DEBIANFILENAME, afterwards delete the just extracted .deb file.

I can't figure out how to do it... I tried different approaches, like

Code:

x='fname='basename $fname deb''

but most likley just don't get it.

Code:

find /dir/ -name *.deb -exec dpkg -x {} /;

try this i havenot tried but just trying to help you

Thanks for the answer !

However I get this upon executing your suggestion:

find: path must preceed expression

Code:

find /dir/ -name "*.deb" -exec dpkg -x {} /;

--ahamed

a little correction

Code:

find /dir/ -name "*.deb" -exec dpkg -x '{}' \;

thanks !

It now says "dpkg needs a target"
Am I doing something wrong ?

are you sure you are executing the same code ygemici gave you?...
Try this...

Code:

find /dir/ -name "*.deb" | xargs -I {} dpkg -x {} {}.x

--ahamed

PS: I am away from my unix box so the code is not tested!