Shell Programming and Scripting

Hello folks. I have read the forum here, almost came close to using some of the hints but too much info so I need a little nudge.

OBJECTIVE: I want to write a script that looks at certain type of files, than move those selected files to another directory, however, keeping the structure (PATH) of the file the same.

EXAMPLE:
if the serached dir is /output and I find a file:
/output/user_a/project_a/abc.txt
I would like this to happen:
mv /user_a/project_a/abc.txt to /code/user_a/project_a/abc.txt

*** basically changing the dir where the file WAS and replacing it with /code but the rest remians the same (so the user does not freak out where his/her file went***

WHAT HAVE I DONE:
I have the find command where I can find the file

find /output -atime +7 -type f -name \*.txt -exec <here I need help> {} ;\

OR
any of you have a better more elegant idea, I would welcome the opportunity to learn.

PS: some of the solutions here have me in awe as how much I don't know. Thx for having the forum.

Assuming that you have same directory structure in the code
directory toooo ....

Code:

dir=$HOME/scripts/abc
a=`find . -name "*.txt"`

for i in $a
do
   j=`echo $i | sed "s/^..//"`
   echo $j
   mv $j  ./code/$j

done

Thank you for your reply. Looks like this will work, however, I am getting the following as a result of the sed command:
+ echo /home/sasadm/setinit.txt
j=ome/sasadm/setinit.txt

I need the /home to drop and do:

j=/code/sasadm/setinit.txt

TIA

I figured it out. Thank you for pushing me in the right direction

I have used the sed because i have used the '.' in the find command.
You may tweak your script based on what you have given in the find command.


Or run my script from where your code directory starts.
And i said before , i asssumes $PWD/code and the directories
under it are existing.

You may create those directories by following single command
if you know the directory structure beforehand.

mkdir -p ./code/dir1/dir2/dir3