Shell Programming and Scripting

Hi,

I want to convert normal time stamp to unix time stamp to a filename.
coz our ssytem will pick depends on unix timestamp format .
the filenames are as shown below fie names are stored in file say temp.txt.


i have variable that converts present time to UNIX time stamp format.

xx=$(date -d "`date`" "+%s")

xx is having presnt unix timestamp value.

now i want replace above file timestamps 1318481547 with newly got timestamp.

i want to do it in loop so that i will get different stamp for each file .

i have done it using awk but its replacing with same timestamp . that i dont want .


let me know any way i can put different timestamp for each filename format in the file using loops.


Thanks,
Raghavendra

Is this what you are looking for:

Code:

#!/usr/bin/ksh
IFS='_'
while read m1 m2 m3 m4; do
  mNewTS=$(date -d "`date`" "+%s")
  mNewFN=${m1}'_'${m2}'_'${m3}'_'${mNewTS}'.dat'
done < Inp_File

That's because xx is a shell variable and you have to pass it to awk using its syntax...

Code:

awk -v myvar=$xx '{ss=substr($1,1,length($1) - 14);aa=substr($1,length($1) - 4,length($1));$1=ss myvar aa ;print $1}' $work_dir/datafile.out > $work_dir/newfile.out