I have a requirement to convert a 12 hour format to 24 hour time format and the sample input /out put is below
Input Time format : Nov 2 2011 12:16AM
Out Put Format : Nov 2 2011 0:16
Input : Nov 2 2011 4:16PM
Out Put: Nov 2 2011 16:16
I have done this using a perl script and working absolutely fine -
###############
###################OUT PUT#############
Nov 2 2011 12:41
Nov 2 2011 12:41
Nov 2 2011 15:41
Nov 2 2011 17:41
My requirement is now :
1) I have file with thousands of records like below and i want to convert each of the records with right time format as i mentioned above.
Nov 2 2011 12:01AM,52893,420,1,4,0,52834,4,1208,67664942,603459924403.0,1,150054,1208,3
Nov 2 2011 5:16PM,52127,420,1,4,0,52122,4,1429,55943831,603459924406.0,1,150054,1429,3
I need to convert the first column match (12:01AM/5:16PM) and convert this to right format
Expected output is :
Nov 2 2011 0:01,52893,420,1,4,0,52834,4,1208,67664942,603459924403.0,1,150054,1208,3
Nov 2 2011 17:16,52127,420,1,4,0,52122,4,1429,55943831,603459924406.0,1,150054,1429,3
I know with little modification to my script this can be acheived but i am not able to match the entire record with regx.
Thanks but i need the entire records - not the date/time part and also your out put has AM/PM which is not needed .
Ex. Input records :
Nov 2 2011 12:01AM,52893,420,1,4,0,52834,4,1208,67664942,603459924403.0,1,150054,1208,3
Nov 2 2011 5:05PM,52127,420,1,4,0,52122,4,1283,151823875,603459924404.0,1,150054,1283,3
Expected out put records:
Nov 2 2011 12:01,52893,420,1,4,0,52834,4,1208,67664942,603459924403.0,1,150054,1208,3
Nov 2 2011 17:05,52127,420,1,4,0,52122,4,1283,151823875,603459924404.0,1,150054,1283,3
If my perl script can be modified to match the records or same sed command equivalent than it will be fine.
Hi,
I have a file where I need to change the date format on the nth field from DD-MM-YYYY to YYYY-MM-DD so I can accurately sort the record by dates
From regex - Use sed or awk to fix date format - Stack Overflow, I found an example using nawk.
Test run as below:
$: cat xyz.txt
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Tue Mar 5 23:44:28 EST 2013
#
this Tue Mar 5 23:44:28 EST 2013
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Hi All,
Can someone please let me know how can i convert the date format in unix as follow:
From: 24 Oct 2011
i.e $(date +'%d %b %Y')
To: 111024
i.e $(date +%y%m%d)
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YYMMDD into a date like YYYY-MM-DD ?
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