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nawk time substracting

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# 1  
Old 10-26-2011
nawk time substracting
Nawk ‘BEGIN {printf “0t%d=Y\n”,srand () -1800}' | adb
I know that printf is printing the value in %d which is for a day of the month and subtracting the value by -1800 (30 minutes).
So if date is 14:25:45 subtracting from 1800 then time will equal to 13:55:45
I also know that srand () is function that is used to set a new seed for the random number generator.
However I don't know what is 0t doing? What is for?Is | adb - debugging the code?
Also what I want is to store the workout value in variable (so every time I run the script it subtracts 30 minutes from current time and stores the value in variable). So I can use the variable in loop which will check all the logs created 30 minutes ago. I can't use gawk
Any help will be greatly appreciated
Thank you all
# 2  
Old 10-26-2011
not sure why you're relying on awk's srand() function getting the current epoch time, but...
Code:
# here's my current EPOCH time
currentEpoch=$(/usr/bin/truss /usr/bin/date 2>&1 | /usr/bin/awk '/^time/ {print $NF}')

# here we convert EPOCH back to human readable format
back2Human=$(echo "0t${currentEpoch}=Y" | /usr/bin/adb)

subtracting '1800' from 'currentEpoch' will get you an epoch time of back 30 minutes from current.
This is all somewhat Solaris specific and may not be portable. There's a 'date/time' arithmetic in the FAQ section that you might find useful.
This User Gave Thanks to vgersh99 For This Post:
INHF
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