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How to parse a string into variables

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# 1  
Old 02-21-2005
How to parse a string into variables
I'm working in korn shell and have a variable which contains a string like:
aa_yyyymmdd_bbb_ccc_ddd.abc. I want to treat the _ and . as delimiters and parse the string so I end up with 6 values in variables that I can manipulate. My original plan was to use
var1=`echo $sting1 | cut -c1-c2` but now the requirements have changed so the position is no longer fixed.

Please help.
# 2  
Old 02-21-2005
Code:
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc"
aa_yyyymmdd_bbb_ccc_ddd.abc
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc"
aa_yyyymmdd_bbb_ccc_ddd.abc
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"." -f 2
abc
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"_" -f 1
aa
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"_" -f 2
yyyymmdd
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"_" -f 3
bbb
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"_" -f 4
ccc
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"_" -f 5
ddd.abc
$ echo "aa_yyyymmdd_bbb_ccc_ddd.abc" | cut -d"_" -f 5 | cut -d"." -f 1
ddd

# 3  
Old 02-21-2005
$ oldIFS=$IFS
$ IFS=._
$ set aa_yyyymmdd_bbb_ccc_ddd.abc
$ set $1
$ echo $1
aa
$ echo $2
yyyymmdd
$ echo $3
bbb
$ IFS=oldIFS
# 4  
Old 02-22-2005
Thanks for the help!
# 5  
Old 05-27-2009
What if we are not sure about the lenght for eg the var can be

aaa_bbb_ccc_ddd.abc
or aaa_bbb.abc
or aaa.abc
# 6  
Old 05-27-2009
Well, you can loop over them.

Code:
-bash-3.2$ cat test.txt
aaa_bbb_ccc_ddd.abc

-bash-3.2$ awk -F"[_.]" '{ for (i = 1; i<=NF;i++) { print $(i); } }' test.txt
aaa
bbb
ccc
ddd
abc

# 7  
Old 05-28-2009
Quote:
Originally Posted by peter35james
What if we are not sure about the lenght for eg the var can be

aaa_bbb_ccc_ddd.abc
or aaa_bbb.abc
or aaa.abc

Ygor's solution works no matter what the lengths are. The only change I'd make is that I'd replace "set $1" with:

Code:
set -f
set -- $1
set +f
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