Shell Programming and Scripting

Hi,

I am looking to write a script to kill the process which are running for more than 7 days.
So i have a command like
"ps -eo pid,etime,args | grep -i xxxx" ( process which has xxx in it and running for more than 7 days needs to be killed ).
When i exeucte the above command , i am getting the ouptut as
4340 2-01:43:00 /bin/ksh /sdfas/sfasd/xxxx/
6178 3-01:41:08 /bin/ksh /sfsf/asfs/xxxx
7573 4-03:25:14 /bin/ksh /sfsf/dfgdfg/xxxx

second fields will tell me the duration of time. How can i convert this duraction to seconds instead of format "days-hour:min:sec".
If i can convert everything to second, i will use awk command like "$2 > seconds " and kill the process.

How can i convert the time to seconds...
Your response is appreciated.
Thanks in Advance.

Code:

$ echo "7573 4-03:25:14 /bin/ksh /sfsf/dfgdfg/xxxx" |
        awk '{ split($2, A, ":"); split(A[1], B, "-"); $2=A[3] + (A[2]*60) + (B[2]*3600)+(B[1]*3600*24) } 1'
7573 357914 /bin/ksh /sfsf/dfgdfg/xxxx
$

Why do you need convert to second, you can use the exist day number to kill directly

Code:

ps -eo pid,etime,args | grep -i xxxx|awk '$2~/-/{split($2,a,/-/);if (a[1]>=7) print $1}' |xargs kill