crontab


 
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# 1  
Old 10-20-2011
crontab

I have crontab entry to run job every first sunday of month :

00 6 1-7 * 0 cmd

but it's running all sundays? what am I missing ?

Thanks
# 2  
Old 10-20-2011
Have you searched the forum? there are multiples posts on the subject
# 3  
Old 10-20-2011
Code:
00 6 1-7 * Sun [ "$(date '+%a')" == "Sun" ] && /path/to/myscript.sh

---------- Post updated at 11:14 AM ---------- Previous update was at 11:08 AM ----------

try this hopefully this works
Code:
 
00 6 1-7 * * [ "$(date '+\%a')" == "Sun" ] && /path/to/myscript.sh

Moderator's Comments:
Mod Comment Video tutorial on how to use code tags in The UNIX and Linux Forums.

Last edited by vbe; 10-20-2011 at 12:27 PM..
# 4  
Old 10-20-2011
Thanks ..it's still failing ..

Your "cron" job on abc
[ "$(date '+\%a')" == "Thu" ] && date > /tmp/date.log

produced the following output:

sh: test: unknown operator ==
# 5  
Old 10-20-2011
You only get == inside [[ ]], not [ ] , and even then only in new BASH/KSH.

Try [ ... = ... ]
# 6  
Old 10-20-2011
test:
Code:
22 * 14-21 * * [ "$(date '+\%a')" = "Thu" ] && date > /tmp/date.log

still not working ...through debug it's showing ...
Code:
ksh -x [ "$(date '+\%a')" = "Thu" ]
+ [ \Thu = Thu ]

but if I remove \ then, syntax error ?

Thanks

Moderator's Comments:
Mod Comment Use code tags, see PM, thanks.

Last edited by zaxxon; 10-20-2011 at 01:52 PM.. Reason: code tags, see PM
# 7  
Old 10-20-2011
I tried this it and it worked, should work now


#testing
03 14 * * * [ "$(date '+\%a')" = "\Thu" ] && /path/to/script > /tmp/
test101.log
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