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conversion of input date in reverse order

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# 1  
Old 10-20-2011
conversion of input date in reverse order
Dear all,

I am having date as input 01-08-2011 ...i want to convert it by removing - (hyphens) in reverse order...i.e 20110801


can u please help me
# 2  
Old 10-20-2011
Quote:
Originally Posted by suryanarayana
...I am having date as input 01-08-2011 ...i want to convert it by removing - (hyphens) in reverse order...i.e 20110801
...
Code:
$
$ echo "01-08-2011" | awk -F- '{print $3$2$1}'
20110801
$
$ # GNU sed
$ echo "01-08-2011" | sed 's/^\([0-9]\+\)-\([0-9]\+\)-\([0-9]\+\)$/\3\2\1/'
20110801
$
$ echo "01-08-2011" | perl -F- -plane '$_="$F[2]$F[1]$F[0]"'
20110801
$
$ echo "01-08-2011" | perl -plane 's/(\d+)-(\d+)-(\d+)/$3$2$1/'
20110801
$
$

tyler_durden
Last edited by durden_tyler; 10-20-2011 at 10:11 AM..
This User Gave Thanks to durden_tyler For This Post:
suryanarayana
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