Shell Programming and Scripting

i have a file which contains alphanumeric data in every line. what i need is the data after certain pattern. the data after the pattern is not of fixed length so i need the data till the space after the pattern.

Input file:
bfdkasfbdfg khffkf lkdhfhdf pattern (datarequired data not required)
jdbfmdsfb kjsdfhfsd dfh pattern (sample jfbjdjf)

desired output file :
datarequired
sample

One approach would be to use egrep to extract the pattern and the following "word" then use sed to replace the pattern with an empty string

Code:

egrep -o 'pattern [^ ]+' infile | sed 's/pattern//'>outfile

Not sure what you after exactly from the description above but the following command will print everything after 'pattern'.

Code:

echo "bfdkasfbdfg khffkf lkdhfhdf pattern 123 this is printed"| perl -ne 'if (/pattern\s+(.*?)$/){print "${1}\n"}'

Output:

Code:

123 this is printed

Regards,
SRG