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awk '{print $ from file1.txt}'

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# 1  
Old 10-17-2011
awk '{print $ from file1.txt}'
Hi All,

I have a file1.txt where the index of the columns are placed. I want to get the columns from file2.txt corresponding to these index numbers.
I was usually using

Code:
awk '{print $5, $6, $2, $3, ...}' file2.txt > output.txt

However, this list is very long. So, i want to read the index from the file1.txt. could you please help me to do that. Thanks.


file1.txt (index for column)

Code:
5,6,2,3,8,9,...

file2.txt (large taxt file)

Code:
D F R T K L K T W Z P ...
F K L W W O T T Z K W ...
.
.

output.txt

Code:
K L  F R T W
W O K L  T Z
...

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!
Last edited by vgersh99; 10-17-2011 at 12:15 PM.. Reason: code tags, please!
# 2  
Old 10-17-2011
Code:
nawk 'FNR==NR {idxN=split($0,idxA,",");next} {for(i=1;i<=idxN;i++) printf("%s%c", $idxA[i], (i==idxN)?ORS:FS)}' file1 file2

And please, start using code tags!
Last edited by vgersh99; 10-17-2011 at 12:28 PM..
# 3  
Old 10-17-2011
Is there any other way to do this without using nawk command. Because it gives me "nawk: command is not found"?
# 4  
Old 10-17-2011
Quote:
Originally Posted by senayasma
Is there any other way to do this without using nawk command. Because it gives me "nawk: command is not found"?
Here is another way, using unix script:
Code:
#!/usr/bin/ksh
set -A mNbr $(sed 's/^/0,/;s/,/ /g' File1)
typeset -i mI
typeset -i mJ
while read mLine; do
  mOut=''
  set -A mLetter $(echo '0 '${mLine})
  mI=1
  while [[ ${mI} -lt ${#mNbr[*]} ]]; do
    mJ=${mNbr[$mI]}
    mOut=${mOut}${mLetter[$mJ]}' '
    mI=${mI}+1
  done
  echo ${mOut}
done < File2

# 5  
Old 10-17-2011
Quote:
Originally Posted by senayasma
Is there any other way to do this without using nawk command. Because it gives me "nawk: command is not found"?
use either awk or gawk.
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